75x^2-160x+80=0

Solution for 75x^2-160x+80=0 equation:

75x^2-160x+80=0

a = 75; b = -160; c = +80;
Δ = b2-4ac
Δ = -1602-4·75·80
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-40}{2*75}=\frac{120}{150}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+40}{2*75}=\frac{200}{150}
=1+1/3
$